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Question

5 kg of water sample contains 0.2 g of fluoride. Calculate the concentration of fluoride ions in terms of ppm.

A
200
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B
4000
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C
400
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D
40
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Solution

The correct option is D 40
Given, mass of F ion= 0.2 g
We know, 1 kg =1000g so 5 kg = 5000g
Concentration of flouride ion in ppm =weight of fluoride ion(g)total weight of water (g)×106
=0.25000×106=40 ppm

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