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Question

5 men and 4 women are to be seated in a row so that the women occupy the even places. How many such arrangements are possible?

A
2880
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B
1440
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C
720
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D
2020
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Solution

The correct option is A 2880
There are total 9 places out of which 4 are even and rest 5 places are odd.
4 women can be arranged at 4 even places in 4! ways.
and 5 men can be placed in remaining 5 places in 5P5 ways,
Hence, the required number of permutations.
=4! ×5P5=24×120=2880

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