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Standard XI

Chemistry

Normality

5 ml of N HCl...

Question

5 ml of N HCl, 20 ml of $N / 2 H_{2} S O_{4}$ and 30 ml of $N / 3 H N O_{3}$ are mixed together and volume made to one litre. The normality of the resulting solution is

\frac{N}{5}

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\frac{N}{10}

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\frac{N}{20}

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\frac{N}{40}

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Solution

The correct option is D $\frac{N}{40}$
$N V = N_{1} V_{1} + N_{2} V_{2} + N_{3} V_{3}$
$N \times 1000 = 1 \times 5 + \frac{1}{2} \times 20 + \frac{1}{3} \times 30 = 5 + 10 + 10 = 25$
$N = 0.025 = \frac{N}{40}$

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Similar questions

5

ml of

1 N

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20

ml of

\frac{N}{2}

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and

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are mixed together and the volume is made to

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L. The normality of the resulting solution is :

5 ml of N HCl, 20 ml of $N / 2 H_{2} S O_{4}$ and 30 ml of $N / 3 H N O_{3}$ are mixed together and volume made to one litre. The normality of the resulting solution is

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5 m L

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and

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are mixed together and volume made to

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Q. 25 mL of a 2 N

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x

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5 ml of N HCl, 20 ml of N/2 H2SO4 and 30 ml of N/3 HNO3 are mixed together and volume made to one litre. The normality of the resulting solution is

The correct option is D N40NV=N1V1+N2V2+N3V3 N×1000=1×5+12×20+13×30=5+10+10=25 N=0.025=N40

5 ml of N HCl, 20 ml of $N / 2 H_{2} S O_{4}$ and 30 ml of $N / 3 H N O_{3}$ are mixed together and volume made to one litre. The normality of the resulting solution is

The correct option is D $\frac{N}{40}$
$N V = N_{1} V_{1} + N_{2} V_{2} + N_{3} V_{3}$
$N \times 1000 = 1 \times 5 + \frac{1}{2} \times 20 + \frac{1}{3} \times 30 = 5 + 10 + 10 = 25$
$N = 0.025 = \frac{N}{40}$