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Question

$$5$$ mole of $${H}_{2}O(l)$$ at $$373K$$ and $$1atm$$ is converted into $${H}_{o}(g)$$ at $$373K$$ and $$5atm$$. Calculate $$\Delta G$$ for this process. (Given:$$R=2Cal/K-mol,\ln{5}=1.6$$).


Solution

Conversion of water to water vapour is a reversible process.
So, $$\triangle G=0$$

Chemistry

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