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Standard XII

Chemistry

First Law of Thermodynamics

5 moles of hy...

Question

5 moles of hydrogen $(γ = \frac{7}{5})$ initially at S.T.P is compressed adiabatically so that its temperature becomes $400^{o} C$ .The increase in internal energy in kilojoules is (R $=$ 8.30 J/mole-K)

21.55

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41.5

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65.55

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80.55

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Solution

The correct option is B 41.5
The increase in the internal energy is given by,
U = $\frac{n R δ T}{γ - 1}$
U = $\frac{5 \times R \times (400 - 0)}{\frac{7}{5} - 1}$
U = $41.57$

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5 moles of hydrogen (γ=75) initially at S.T.P is compressed adiabatically so that its temperature becomes 400oC.The increase in internal energy in kilojoules is (R = 8.30 J/mole-K)

The correct option is B 41.5The increase in the internal energy is given by,U = nRδTγ−1U = 5×R×(400−0)75−1U = 41.57

5 moles of hydrogen $(γ = \frac{7}{5})$ initially at S.T.P is compressed adiabatically so that its temperature becomes $400^{o} C$ .The increase in internal energy in kilojoules is (R $=$ 8.30 J/mole-K)

The correct option is B 41.5
The increase in the internal energy is given by,
U = $\frac{n R δ T}{γ - 1}$
U = $\frac{5 \times R \times (400 - 0)}{\frac{7}{5} - 1}$
U = $41.57$