CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

5 years hence, the age of a man shall be 3 times the age of his son while 5 years earlier the age of the man was 7 times the age of his son.The present age of the man is

(a) 45 years (b) 50 years (c) 47 years (d) 40 years

Open in App
Solution

Let the age of son 5 years earlier = x
So, age of father 5 years earlier = 7x

Now, present ages of son and father are x+5 and 7x+5.

5 years hence, age of son = x+10
5 years hence, age of father = 7x+10

Given 7x+10 = 3 × (x+10)
7x+10 = 3x+30
4x = 20
x = ​​​​​​​5

Hence, the present age of man is 7 × 5 + 5 = 40 years.


flag
Suggest Corrections
thumbs-up
36
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Linear Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon