Question

# 50 g of copper is heated to increase its temperature by 10∘C. If the same quantity of heat is given to 10 g of water, what will be the rise in its temperature? Assume no state change. Specific heat of copper =420 J kg−1 ∘C Specific heat of water =4200 J kg−1 ∘C

A

5C

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B

6C

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C

7C

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D

8C

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Solution

## The correct option is A 5∘C Same amount of heat is supplied to copper and water. mcccΔTc = mωcωΔTω where mc: Mass of copper mw: Mass of water, cc: Specific heat of copper cw: Specific heat of water ΔTc: Temperature difference of copper ΔTw: Temperature difference of water ΔTw=mcccΔTcmwcw ΔTw=50×10−3×420×1010×10−3× 4200 ΔTw=5∘C

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