50 g of metal piece at 27-C requires 2400 J of heat energy so as to attain a temperature of 327-C- Calculate the specific heat capacity of the metal-

Given: m = 50g; t = 327^∘C 27^∘C = 300^∘C, Q = 2400 J Now, Q = mc t 2400 = 50× C × 300 Specific heat capacity of the metal, c = 240050× 3 ...

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Byju's Answer

Standard XII

Physics

Specific Heat Capacity

50 g of metal...

Question

$50 g$ of metal piece at $27^{\circ} C$ requires $2400 J$ of heat energy so as to attain a temperature of $327^{\circ} C$ . Calculate the specific heat capacity of the metal.

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Solution

Given: $m = 50 g; △ t = 327^{\circ} C - 27^{\circ} C = 300^{\circ} C, Q = 2400 J$
Now, $Q = m c △ t$
$2400 = 50 \times C \times 300$
Specific heat capacity of the metal, $c = \frac{2400}{50 \times 300} = 0.16 J / g^{\circ} C$

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