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Question

50 gm of copper is heated to increase its temperature by 10C. If the same quantity of heat is given to 10 gm of water, the rise in its temperature is (Specific heat of copper =420 Joulekg1C1)
  1. 6C
  2. 7C
  3. 5C
  4. 8C


Solution

The correct option is C 5C
Same amount of heat is supplied to copper and water so,
Heat absorbed by copper = heat absorbed by water 
heat absorbed = mass × specific heat × temperature difference 
mcccΔθc=mWcWΔθW
where, mc = mass of copper 
mW = mass of water
cc = specific heat of copper
cW = specific heat of water 
(Δθ)c = rise in temperature for copper
(Δθ)W = rise in temperature for water 
ΔθW=mccc(Δθ)cmWcW=50×103×420×1010×103×4200=5C

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