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Question

50 mL of 1 M HCl, 100 mL of 0.5 M HNO3, and x mL of 5 M H2SO4 are mixed together and the total volume is made upto 1.0 L with water. 100 mL of this solution exactly neutralises 10 mL of M/3 Al2(CO3)3. Calculate the value of x:___


Solution

Total mEq of acid = 50×1+100×0.5+x×5×2 (n factor)
                            = (100 + 10x)mEq
                        =(100+10x)100 mLN
N1V1(Acid)=N1V1[Al2(CO23)3] (Total charge = 6)
(n = 6)
 (100+10x)100 mLN×100mL=10mL×13×6
(100 + 10x) = 200
x = 10 mL 

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