    Question

# 50 mL of 1 M oxalic acid (molar mass =126) is shaken with 0.5 g of wood charcoal. The final concentration of the solution after adsorption is 0.5 M. What is the amount of oxalic acid adsorbed per gram of carbon?

A
3.15
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B
1.575
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C
6.30
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D
12.60
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Solution

## The correct option is C 6.30Initial Molarity of Oxalic Acid = 1M Final Molarity of Oxalic Acid = 0.5MWe know, Molarity = MolesVolumeMoles = Molarity×VolumeHence, Initial number of molesc=> mi = 1M×50mL =>mi = 50m−moles = 50×10−3Moles Similarly, Final number of moles (mf) = 0.5M×50mL=> mf = 25m−moles = 25×10−3MolesMoles of oxalic acid adsorbed =(50−25) m-moles =25 m-molesMoles of oxalic acid adsorbed per gram Carbon = 25×10−3Moles0.5g =0.05 molesMass of oxalic acid adsorbed = 0.05×126 =6.30g  Suggest Corrections  0      Similar questions  Related Videos   Mole Concept
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