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Equivalent Mass

50 mL of a mi...

Question

50 mL of a mixture of NaOH and $N a_{2} C O_{3}$ titrated with
$\frac{N}{10}$ HCl using phenolpthalien indicator required 50ml of HCl to decolour isephenolpthalien. At this stage methyl orange was added and addition of acid was continued. The second end point was reached after further addition of 10ml of $\frac{N}{10}$ . The amount of NaOH in the solution is:

A

3.2g

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B

0.16g

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C

0.08g

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D

0.4g

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Solution

The correct option is B 0.16g
$1^{s t}$ titration
Meq. Of NaOH + $\frac{1}{2}$ meq of $N a_{2} C O_{3}$ = meq of HCL = $50 \times \frac{1}{10} = 5$
$2^{n d}$ titration
$\frac{1}{2}$ meq of $N a_{2} C O_{3}$ = meq. of HCL = $10 \times \frac{1}{10} = 1$
$∴$ M eq of NaOH = 5 - 1 = 4
Lot of NaOH = $\frac{4 \times 40}{100} = 0.16 g r$

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Similar questions

25 m L

of a mixture of

N a O H + N a_{2} C O_{3}

, when titrated with

\frac{N}{10} H C l

using phenolphthalein indicator required

25 m L H C l

to decolourise phenolphthalein. At this stage, methyl orange was added and the addition of acid was continued. The second endpoint was reached after further addition of

5 m L

of the acid. Calculate the amount of

N a_{2} C O_{3}

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in one litre of the solution.

Q. A mixture of

N a O H

N a_{2} C O_{3}

solution is titrated with

50 mL

\frac{N}{10} H C l

using phenolpthalein. At this stage methyl orange was added and addition of acid was continued. The second end point was reached after further addition of

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Q. 200 mL of a solution mixture

N a O H

N a_{2} C O_{3}

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Equivalent Mass

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