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Question

50 ml of a solution containing 103 mol of Ag+ is mixed with 50 ml of a 0.1 M HCl solution. How much Ag+ remains in solution? (Ksp of AgCl=1.0×1010)

A
2.5×109
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B
2.5×107
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C
2.5×108
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D
2.5×1010
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Solution

The correct option is C 2.5×108
Ag+1×103 mol+Cl5×103 molAgCl(s)
[HCl]=50 ml×0.1 M
=5.0 mmol=5.0×103 mol
[H+]=[Cl]=5×103 mol
All of the silver reacts with the chloride ions and then starts to dissociate to form silver ions again.
[Cl]=4×103 mol after the reaction.
[Ag+]=1.0×10104.0×103=2.5×108 mol

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