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Question

50 mL of a solution of magnesium hydroxide on titration with a 0.1 M solution of HCl gave a titre value of 70 mL. The molarity of magnesium hydroxide solution is:

A
0.07 M
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B
0.14 M
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C
0.28 M
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D
0.35 M
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Solution

The correct option is A 0.07 M
Let, the molarity of Mg(OH2) solution be: x M
So, n1×M1×V1=n2×M2×V2
where, n1=nfactor of Mg(OH)2=2
M1=molarity of Mg(OH)2=x M
V1=volume of Mg(OH)2=50 mL
n2=nfactor of HCl=1
M2=molarity of HCl=0.1 M
V2=volume of HCl=70 mL
2×x×50=1×0.1×70
x=7100=0.07
The molarity of Mg(OH2) solution = 0.07 M

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