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Question

50 mL of an aqueous solution of H2O2 was treated with an excess of KI solution and dilute H2SO4. The liberated iodine required 20 mL 0.1 N Na2S2O3 solution for complete interaction. Calculate the concentration of H2SO2 in g/L.

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Solution

H2O2+2KI+H2SO4K2SO4+2H2O+I2
2Na2S2O3+I2Na2S4O6+2NaI
Eq. mass H2O2=342=17
20 mL 0.1 N Na2S2O3=20 mL 0.1 N I2 solution
20 mL 0.1 N H2O2 solution
Amount of H2O2 in 50 mL aq. solution
=0.1×171000×20=0.034 g
Concentration in g/L=0.03450×1000=0.68.

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