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Question

50 Wm2 energy density of sunlight is normally incident on the surface of a solar panel. Some part of incident energy (25%) is reflected from the surface and the rest is absorbed. The force exerted on 1 m2 surface area will be close to- (c=3×108 ms1)

A
15×108 N
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B
10×108 N
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C
35×108 N
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D
20×108 N
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Solution

The correct option is D 20×108 N
For a partially reflecting and absorbing surface,

F=(1+r)IAC
=(1+0.25)×50×13×108
20×108 N
<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (B) is the correct answer.

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