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Question

500 mL of a N5H2SO4 and 200 ml of N10NaOH are mixed. What will be the normality of H+ ions in the solution?
  1. 0.114 N
  2. 0.328 N
  3. 0.256 N
  4. 0.780 N


Solution

The correct option is A 0.114 N
Number of milliequivalents = Normality × volume in mL
Number of milliequivalents of H2SO4 =15×500=100 milliequivalents
Number of milliequivalents of NaOH
=110×200=20 milliequivalents
After mixing of the acid and the base, milliequivalents of H+ ions=10020=80 milliequivalents
Normality of H+ ions:  
milliequivalents total volume of the solution in mL=80700=0.114 N

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