The correct option is D 3775 This is an A.P in which a=51,l=100,n=50 ∴ Sum =n2(a+l)=502× (51+100)=(25× 151)=3775 ...

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Sum of n Terms

51+52+53+.......

Question

$(51 + 52 + 53 + . . . . . . . + 100) =$ ?

2525

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2975

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3225

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3775

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Solution

The correct option is D $3775$
This is an A.P in which $a = 51, l = 100, n = 50$
$∴$ Sum $= \frac{n}{2} (a + l) = \frac{50}{2} \times (51 + 100) = (25 \times 151) = 3775$

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Similar questions

51 + 52 + 53 + ……. + 70

The coefficient of $x^{53}$ in $\sum_{r = 0}^{100}^{100} C_{r} (x - 3)^{100 - r} 2^{r}$ is

\times

\times

\times

\times

(2^{51} + 2^{52} + 2^{53} + 2^{54} + 2^{55})

A = ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} \frac{2}{3} \frac{1}{3} \frac{7}{3} \end{matrix} \begin{matrix} 1 \frac{2}{3} 2 \end{matrix} \begin{matrix} \frac{5}{3} \frac{4}{3} \frac{2}{3} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦

B = ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} \frac{2}{5} \frac{1}{5} \frac{7}{5} \end{matrix} \begin{matrix} \frac{3}{5} \frac{2}{5} \frac{6}{5} \end{matrix} \begin{matrix} 1 \frac{4}{5} \frac{2}{5} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦

3 A - 5 B

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