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Magnetic Compass

54.A magnetic...

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54.A magnetic needle is free to rotate in a vertical plane which makes an angle of. 60^° with the magnetic meridian. It' the needle stays in a direction making an angle of 1/tan(2 under root 3) with the horizontal, what would be the dip at that place ?

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A magnetic needle is free to rotate in a vertical plane which makes an angle of $60^{0}$ with the magnetic meridian. If the needle stays in a direction making an angle of tan $^{- 1} (\frac{2}{\sqrt{3}})$ with the horizontal, what would be the dip at that place ?

Q. If a dip circle is placed in a vertical plane at an angle of

30^{o -}

to the magnetic meridian, the dip needle makes an angle of

45^{o -}

with the horizontal. The real dip at that place is?

Q. A magnetic needle freed to rotate around a fixed vertical plane stay at an angle

60^{0}

with the horizontal . If the dip at that place is

37^{0}

, find the angle of the fixed vertical plane with the meridian.

Q. A dip circle is adjusted so that its needle moves freely in the magnetic meridian. In this position, the angle of dip is

40^{\circ}

. Now the dip circle is rotated so that the plane in which the needle moves makes an angle of

30^{\circ}

with the magnetic meridian. In this position the needle will dip by an angle

If the magnet is suspended at an angle 30^o to the magnetic meridian, the dip needle makes an angle 60^o with the horizontal. What is the true dip?

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