56. (logbase4 32)log16 4)(log64 2)

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\frac{c o s^{2} 56^{\circ} + c o s^{2} 34^{\circ}}{s i n^{2} 56^{\circ} + s i n^{2} 34^{\circ}} + 3 t a n^{2} 56^{\circ} \times t a n^{2} 34^{\circ} =

Solve: (7 + p) (8 + p)

\frac{{cos}^{2} 56^{o} + {cos}^{2} 34^{o}}{{sin}^{2} 56^{o} + {sin}^{2} 34^{o}} + 3 {tan}^{2} 56^{o} {tan}^{2} 34^{o}

The area of a triangle with sides 14 cm, 16 cm and 26 cm and semi-perimeter 28 cm is

(56)^{2} - (55)^{2}

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