Question

560 ml of carbon monoxide is mixed with 500 ml of oxygen and ignited. The chemical equation for the reaction is as follows:

$2CO+O_2\to 2C{O}_2$

Calculate the volume of oxygen used and carbon dioxide formed in the above reaction.

• A. 661 ml CO₂ , 200 ml O₂
• B. 617 ml CO₂ , 300 ml O₂
• C. 579 ml CO₂, 150 ml O₂
• D. 544 ml CO₂, 240 ml O₂
• E. 602 ml CO₂, 350 ml O₂
• F. 560 ml CO₂, 280 ml O₂

Answer 1

The correct option is F

560 ml CO₂, 280 ml O₂

According to Gay Lussac’s law:

2CO + $O_2$ → $2C{O}_2$

2 vol. 1 vol. 2 vol.

1 vol. $\frac{1}{2}$ vol. 1 vol.

560 ml $\frac{560}{2}$ ml 560 ml

560 ml 280 ml 560 ml

The volume of oxygen used is 280ml and the volume of carbon dioxide formed is 560 ml.