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Byju's Answer
Standard VI
Mathematics
Organised Data
5,78=27 and 4...
Question
5,78=27 and 4,12,10=38;then 13,6,?=63
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Q.
Evaluate the determinant:
∣
∣ ∣
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Cosec²63°+tan²24/cot²66+sec²27| +|sin²63+cos63sin27+sin27sec63/2(cosec²65-tan²65)
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The L.C.M of 27, 63 and 54 is
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3cot 31° tan 15° cot 27° tan 75° cot 63° cot 59°
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