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Byju's Answer
Standard VIII
Chemistry
Reaction of Metals with Acid
5g of Mn 2nd ...
Question
5g of Mn 2nd on reaction with HCl forms 1.12L of Cl2 gas at STP.The %impurity of Mn 2nd is?
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Q.
M
n
O
2
+
4
H
C
l
→
2
H
2
O
+
M
n
C
l
2
+
C
l
2
The reaction of
M
n
O
2
and
H
C
l
produces
2.24
L
of
C
l
2
gas. What mass of
M
n
O
2
was used up by the reaction? (At. mass of
M
n
=
55
g
/
m
o
l
)
Q.
10
g of
M
n
O
2
on reaction with conc.
H
C
l
liberated
0.1
equivalent of
C
l
2
(molecular weight of
M
n
=
55
g/mol). Hence, percentage purity of
M
n
O
2
is
:
Q.
Calculate the weight of
M
n
O
2
.
H
C
l
of specific gravity
1.2
g/mL and
5
%
by weight needed to produce
1.12
L
of
C
l
2
at STP by the reaction (as nearest integer).
M
n
O
2
+
4
H
C
l
→
M
n
C
l
2
+
3
H
2
O
+
C
l
2
Q.
If
x
g of
M
n
O
2
and the volume of
H
C
l
of specific gravity
1.2
g
m
L
−
3
and
5
%
by weight needed to produce
1.12
L
of
C
l
2
at STP by the reaction,
M
n
O
2
+
4
H
C
l
→
M
n
C
l
2
+
3
H
2
O
+
C
l
2
then value of 100X is
:
Q.
For the reaction :
M
n
O
2
+
4
H
C
l
100
%
−
−−
→
M
n
C
l
2
+
C
l
2
+
2
H
2
O
,
17.4
g
M
n
O
2
is dissolved in
500
m
L
of
H
C
l
solution containing
7.3
g
H
C
l
per litre. (molar mass of
M
n
=
55
g
/
m
o
l
)
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