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Question

6.02×1020 molecules of urea are present in 100 mL of its solution. The molarity of urea solution is :

A
0.1
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B
0.01
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C
0.02
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D
0.001
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Solution

The correct option is B 0.01
M=moleofureavolumeinlitre=6.02×10206.02×1023×1001000=0.01M

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