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Question

6.022 × 1020 molecules of urea are present in 100 ml of its solution. The concentration of urea solution is_________.

A
0.001 M
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B
0.01 M
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C
0.02 M
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D
0.1 M
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Solution

The correct option is B 0.01 M
Given
6.02*1020 molecules of urea
volume of solution is 100/1000=0.1 L
Solution
1 mole of urea have 6.02*1023 molecules
no.of moles present=6.02*1020/6.02*1023=103
Concentration of Urea will be
103/0.1=0.01M
The correct option is B

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