6. Prove that sin20sin40sin60sin80=3/16

Open in App

Solution

Suggest Corrections

Similar questions

s i n (20) s i n (40) s i n (60) s i n (80) = \frac{1}{16}

sin 20^{\circ} sin 40^{\circ} sin 60^{\circ} sin 80^{\circ} = \frac{3}{16}

sin 50^{o} . sin 60^{o} . sin 70^{o} . sin 170^{o} = \frac{\sqrt{3}}{16}

cos 10^{0} cos 30^{0} cos 50^{0} cos 70^{0} = \frac{3}{16}

{log}_{12} 27 = a .

{log}_{6} 16 = \frac{4 (3 - a)}{3 + a} .

Join BYJU'S Learning Program