60-45-455010 605-10- So 60-45-

5 + 10 = 15 So, 60 − 45 = nbsp;15 nbsp; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Conditional Identities

60-45=?455010...

Question

60 − 45 = ?

5 + 10 = ______

So 60 − 45 =

Open in App

Solution

Suggest Corrections

Similar questions

x sin 45^{o} . cos 45^{o} . tan 60^{o} = tan 45^{o} - cos 60^{o}

60^{\circ}

45^{\circ}

60^{\circ}

45^{\circ}

2 ({cos}^{2} 45^{\circ} + {tan}^{2} 60^{\circ}) - 6 ({sin}^{2} 45^{\circ} - {tan}^{2} 30^{\circ}) = 6

2 ({cos}^{4} 60^{\circ} + {sin}^{4} 30^{\circ}) - ({tan}^{2} 60^{\circ} + {cos}^{2} 45^{\circ}) + 3 {sec}^{2} 30^{\circ} = \frac{3}{4}

Solve : $\frac{sin 30^{\circ} + tan 45^{\circ} - c o s e c 60^{\circ}}{sec 30^{\circ} + cos 60^{\circ} + cot 45^{\circ}}$

2 {tan}^{2} 45^{\circ} + {cos}^{2} 30^{\circ} - {sin}^{2} 60^{\circ} + tan 45^{\circ} / cot 45^{\circ} .

Join BYJU'S Learning Program