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64. Integrati...

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64. Integration of 1/6xdx

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\int_{1}^{4} f (x) d x

, find this where

f (x) = {\begin{matrix} 7 x + 3 & 1 \leq x \leq 3 8 x & 3 \leq x \leq 4 \end{matrix}

\int_{- 1}^{4} f (x) d x = 4

\int_{2}^{4} [3 - f (x)] d x = 7

, then the value of

\int_{- 1}^{2} f (x) d x

4 \int - 1 f (x) d x = 4

4 \int 2 (3 - f (x)) d x = 7

, then which of the following is/are true:

\int_{1}^{4} f (x) d x

f (x) = x^{2}

1 \leq x < 2

f (x) = 3 x; 2 \leq x < 4

f (x)

is continuous in

(- 1, 4)

\int_{- 1}^{4} f (x) d x = 4

\int_{2}^{4} (3 - f (x)) d x = 7

\int_{- 1}^{2} f (x) d x =

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