68.Prove that Tan50+sec50=tan70

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t a n 10^{\circ} + t a n 70^{\circ} - t a n 50^{\circ} = \sqrt{3}

\frac{tan 70^{\circ} - tan 20^{\circ}}{tan 50^{\circ}}

Find the value of: tan 20^o. tan 40^o. tan 50^o. tan 60^o. tan 70^o

tan 10^{\circ} tan 20^{\circ} tan 30^{\circ} tan 40^{\circ} tan 50^{\circ} tan 60^{\circ} tan 70^{\circ} tan 80^{\circ}

\frac{2 sin 68^{\circ}}{cos 22^{\circ}} - \frac{2 cot 15^{\circ}}{5 tan 75^{\circ}} - \frac{3 tan 45^{\circ} tan 20^{\circ} tan 40^{\circ} tan 50^{\circ} tan 70^{\circ}}{5}

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