Question

-6x + 4y = 2 ;
3x + 2y = -1
Consider the system of equations above. If (x, y) is a solution of the equations above, then how many possible values are there for (x, y) ?

• A. No solution
• B. One solution
• C. Infinitely many solutions
• D. None of the above

Answer 1

The correct option is B One solution

Ratio of coefficients of $x=-\frac{6}{3}=-2$
Ratio of coefficients of $y=-\frac{4}{2}=2$
Ratio of constant terms $x=\frac{2}{-1}=-2$
Therefore, the system of equations has a unique solution.