6 x2-17 x-5-a 2 x-13 x-5b 2 x-53 x-1c 6 x-5x-1d none of these

(b) (2x + 5)(3x + 1) 6x2+17x+5=6x2+15x+2x+5 nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; =3x2x+5+12x+5=2x+53x+1 ...

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6 x2+17 x+5=?...

Question

6x² + 17x + 5 = ?
(a) (2x + 1)(3x + 5)
(b) (2x + 5)(3x + 1)
(c) (6x + 5)(x + 1)
(d) none of these

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$6 x^{2} + 17 x + 5$ =?

(a) $(2 x + 1)$

(b) $(2 x + 5) (3 x + 1)$

(d) None of these

x

\frac{6 x^{2} + 13 x - 4}{2 x + 5} = \frac{12 x^{2} + 5 x - 2}{4 x + 3}

\frac{6 x^{2} + 13 x - 4}{2 x + 5} = \frac{12 x^{2} + 5 x - 2}{4 x + 3}

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