$7^{2} + 1^{2} = . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .$
$(7 + 1)^{2} = . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .$
What should be added to $7^{2} + 1^{2}$ to got $(7 + 1)^{2} ?$

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Solution

$7^{2} + 1^{2} = 49 + 1 = 50$
$(7 + 1)^{2} = 8^{2} = 64$

Hence, $14$ should be added into $7^{2} + 1^{2}$ to get $(7 + 1)^{2} .$

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