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Standard XII
Chemistry
Osmosis
7.5 ml of a g...
Question
7.5 ml of a gaseous hydrocarbon was burnt with excess oxygen. On cooling the volume contracted by 15 ml Find the formula of the hydrocarbon if the vapour density is 14
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Similar questions
Q.
7.5
m
L
of a hydrocarbon gas was exploded with an excess of oxygen. On cooling, it was found to have undergone a contraction of 1
5
m
L
. If the vapour density of the hydrocarbon is
14
, determine its molecular formula.(C=12, H=1)
Q.
A gaseous hydrocarbon (
12
ml) is exploded with an excess of oxygen. On cooling, the contraction in volume is
48
ml and there is further contraction of
48
ml in volume when passed through
C
O
2
. The molecular formula of hydrocarbon is:
Q.
7.5 ml of a gaseous hydrocarbon was exploded with 36 ml of
O
2
. On cooling, the volume of gases was found to be 28.5 ml, 15 ml of which was absorbed by
K
O
H
and the rest was absorbed in a solution of alkaline pyrogallol. The formula of hydrocarbon is:
Q.
15
mL
of a gaseous hydrocarbon was required for complete combustion in
357.15
mL
of air (
21
%
of oxygen by volume) and the gaseous products occupied
327
mL
(all volumes being measured at NTP). What is the formula of the hydrocarbon?
Q.
Ten milliliters of a gaseous hydrocarbon was burnt completely in 80 ml of
O
2
at STP. The Volume of the remaining gas is 70 ml. The volume became 50 ml on treatment with NaOH. The formula of the hydrocarbon is :
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