76.Prove that. Tan(b+c)+ tan(c+a)+ tan (a+b)/tan(-a)+ tan (2-b)+ tan (3-c)=1

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t a n A + t a n B + t a n C = 3 \sqrt{3}

Δ A B C

tan A + tan B + tan C = tan A tan B tan C

k = (sec A + tan A) (sec B + tan B) (sec C + tan C)

sec A

- tan A

sec B

- tan B

sec C

- tan C

k

A + B + C = π

tan (A / 2) tan (B / 2) + tan (B / 2) tan (C / 2) + tan (C / 2) tan (A / 2) = 1

If A+B+C=180°, prove that

tan(A/2)tan(B/2)+ tan(B/2)tan(C/2)+ tan(C/2)tan(A/2)= 1

If $\frac{c o s (A - B)}{c o s (A + B)} + \frac{c o s (C + D)}{c o s (C - D)} = 0$ , prove that $t a n A t a n B t a n C t a n D = - 1$

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