$7 E_{H}$ and $5 F_{H}$ are XORed. The output is multiplied by $10_{H}$ . The result is

0210_{H}

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7 E 5 F_{H}

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5 F 7 E_{H}

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2100_{H}

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Solution

The correct option is A $0210_{H}$
$7 E_{H} \to 01111110$
$5 F_{H} \to 01011111 - --------- -$
$X O R e d \to 00100001 - --------- - = 21 H$

$21_{H}$
$\times 10_{H} - ---- -$
$R e s u l t \to 0210_{H} - ----- -$

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