8 pipes take 21 hrs to fill a drum. If 1 pipe is damaged, then the total time taken to fill the drum will be .

21 hours

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24 hours

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30 hours

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Solution

The correct option is B 24 hours
We know that
$Number of pipes (x) \propto \frac{1}{Time taken (y)}$
$∴ \frac{x_{1}}{x_{2}} = \frac{y_{2}}{y_{1}}$

Given,
$x_{1} = 8 p i p e s$
$y_{1} = 21 h o u r s$
$x_{2} = 8 - 1 = 7 p i p e s$
$and y_{2} = Time taken by 7 pipes$
$y_{2} = \frac{8 \times 21}{7} = 24 h o u r s$

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8 pipes take 21 hrs to fill a drum. If 1 pipe is damaged, then the total time taken to fill the drum will be .

The correct option is B 24 hoursWe know that Number of pipes(x)∝1Time taken(y) ∴x1x2 = y2y1 Given, x1 = 8 pipes y1 = 21 hours x2 = 8 − 1 = 7 pipes and y2 = Time taken by 7 pipes y2 = 8×217 = 24 hours