81.A dip needle initially lies in magnetic meridian when it shows angle of dip theta there .The dip circle is rotated through an angle x in the horizontal plane , and dip angle in that plane is theta'.

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Q. A dip needle lies initially in the magnetic meridian when it shows an angle of dip

θ

at a place. The dip circle is rotated through an angle

x

in the horizontal plane and then it shows an angle of dip

θ^{'}

. Then

\frac{tan θ^{'}}{tan θ}

Q. A dip needle lies initially in the magnetic meridian when it shows an angle of dip

θ

at a place. The dip circle is rotated through an angle

x

in the horizontal plane and then it shows an angle of dip

θ

'. Then

\frac{tan θ^{^{'}}}{tan θ}

Q. A dip needle lies initially in the magnetic meridian when it shows an angle of

d i p θ

at a place. The dip circle is rotated through an angle

x

in the horizontal plane and then it shows an angle of

d i p θ^{'}

. Then,

\frac{tan θ^{^{'}}}{tan θ}

will be

Q. A dip needle lies initially in the magnetic meridian when it shows an angle of dip q at a place. The dip circle is rotated through an angle x in the horizontal plane and then it shows an angle of dip

θ^{'}

. Then

\frac{t a n θ^{'}}{t a n θ}

A dip needle shows an angle of dip $θ$ in a place which is in the magnetic meridian. Now, the dip circle is rotated through an angle $x$ in the horizontal plane and then it shows an angle of dip $θ_{1} .$ Value of $tan θ_{1} / tan θ$ is :

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