CameraIcon

SearchIcon

MyQuestionIcon

Thermal Expansion

88.the radius...

Question

88.the radius of earth is 6400km. at what depth from surface of the earth is the time period of a simple pendulum is 1% more than that on the surface of earth?

Open in App

Solution

Suggest Corrections

thumbs-up

0

mid-banner-image

mid-banner-image

Similar questions

Q. At what depth from the surface of earth the time period of a simple pendulum is

0.5 %

more than that on the surface of the earth? (Radius of earth is

6400 km

)

Q. At what depth from the surface of earth the time period of a simple pendulum is

5 %

more than that on the surface of the Earth?

(

Radius of earth is

6400 k m)

Q. At what depth from the surface of earth, the time period of a simple pendulum is

0.5 %

more than that on the surface of the earth?

(

Radius of earth is

6400 km)

Q. Show that the period of oscillation of simple pendulum at depth h below earths surface is inversely proportional to

\sqrt{R - h}

where R is the radius of earth. Find out the time period of a second pendulum at a depth R/2 from the earths surface?

Q. At which height from the surface of the Earth, The acceleration due to gravity is the same as at a depth 160 km below the surface of Earth. Radius of Earth is 6400 km

View More

Join BYJU'S Learning Program

Select...

similar_icon

Related Videos

lock

Thermal Expansion

PHYSICS

Watch in App

explore_more_icon

Explore more

Thermal Expansion

Standard XII Physics

Join BYJU'S Learning Program

Select...