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Question

(9 mL\) of mixture of methane and ethylene when exploded with 30ml (excess) of Oxygen. After

Cooling the volume was 21.0ml. Further treatment with caustic potash reduced the volume to 7ml.

The amounts of methane and ethylene is the mixture respectively are


A

5ml of CH4 + 4ml of C2H4

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B

4ml of CH4 + 5ml of C2H4

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C

3ml of CH4 + 6ml of C2H4

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D

6ml of CH4 + 3ml of C2H4

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Solution

The correct option is B

4ml of CH4 + 5ml of C2H4


Let the volume of CH4=X ml

Volume of C2H4=(9-x)mL

(i) VH4+2O2 CO2+2H2O

.x ml 2x mL x ml negligible volume

(ii) C2H4 + 3O2 CO2+2H2O

(9-x)mL 3(9-x)mL (9-x)mL

(Volume of after contraction and cooling i.e volume of O2 left unused=7ml

Volume of CO2 Produced + O2 left un-used=7ml

of CO2=21-7=14ml

Total volume of CO2 produced from CH4&C2H4

=X mL~+~2(9-x) mL=14 mL

Volume of CH4=4mL and that of C2H4=9-x=9-4=5 mL


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