Question

$9$ moles of $D$ and $14$ moles of $E$ are allowed to react in a closed vessel according to given reactions. Calculate the number of moles of $B$ formed at the end of the reaction, if $4$ moles of $G$ are present in the reaction vessel. (Percentage yield of the reaction is mentioned in the reaction).
Step 1: $3D+4E\stackrel{80\%}{\to }5C+A$
Step 2: $3C+5G\stackrel{50\%}{\to }6B+F$

• A. $1.2$
• B. $30$
• C. $4.8$
• D. $1$

Answer 1

The correct option is A $1.2$

Step 1 $3D+4E\stackrel{80\%}{\to }5C+A$
Step 2 $3C+5G\stackrel{50\%}{\to }6B+F$
Moles of G in reaction vessel = 4 moles
moles of D = 9 moles.
moles of E = 14 moles
$3D+4E\stackrel{80\%}{\to }5C+A$
$t=09moles14moles00$
t = t 9 - 7.2 14- 9.6 (12 month - x) 2.4 moles
$3c+5G\to 6b+F$
$12-x$ 4 moles - 2 moles 2.4 0.4
$=12-1.2$
$x=1.2$ moles