90.General solution of 3tan(-15)=tan(+15)

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3 tan (A - 15^{\circ}) = tan (A + 15^{\circ})

3 tan (θ - 15^{o}) = tan (θ + 15^{o}), 0 < θ < 90^{o}

θ = 45^{o}

({tan}^{- 1} x)^{2} - 3 {tan}^{- 1} x + 2 \geq 0

{({tan}^{- 1} x)}^{2} - 3 {tan}^{- 1} x + 2 \geq 0

3 tan (θ - 15^{o}) = tan (θ + 15^{o}), 0^{o} < θ < 90^{o}

sin θ + cos θ

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