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Question

$$_{92}U^{235} + n \rightarrow $$ fission product+neutron + $$ 3.20 \times 10^{-11}J$$. The energy released when 1g of $$_{92}U^{235}$$ undergoes fission is:


A
12.75×108 kJ
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B
18.60×109 kJ
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C
8.21×107 kJ
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D
6.55×106 kJ
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Solution

The correct option is C $$8.21 \times 10^7 \ kJ$$
$$1 g u - 235 = \dfrac{6.023 \times 10^{23}}{235}$$ atoms

$$\therefore$$ Energy released = $$3.2 \times 10^{-11} \times \dfrac{6.023 \times 10^{23}}{235} J = 8.21 \times 10^{10}J = 8.2 \times 10^7 kJ$$.

Chemistry
NCERT
Standard XII

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