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Standard Values of Trigonometric Ratios

93.If sinA + ...

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93.If sinA + sinB + sinC = 3 Then find the value of cosA + cosB + cosC

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cos a + cos b + cos c = sin a + sin b + sin c = 0

cos (a - b) + cos (b - c) + cos (c - a) = - \frac{3}{2}

.

cos (B - C) + cos (C - A) + cos (A - B) = - \frac{3}{2}

cos A + cos B + cos C = 0

sin A + sin B + sin C = 0

Δ A B C

sin A + sin B + sin C = \sqrt{2} + 1

cos A + cos B + cos C = \sqrt{2}

, then the triangle is

A + B + C = π

cos A + cos B + cos C

= 0 = sin A + sin B + sin C

cos 3 A + cos 3 B + cos 3 C = 1

△ A B C, s i n A + s i n B + s i n C = 1 + \sqrt{2}

c o s A + c o s B + c o s C = \sqrt{2}

if the triangle is

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