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Inequalities of Integrals

94. f(x)f(1÷ ...

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94. f(x)f(1÷ x)=f(x)+f(1÷ x); and f(3)=-26,find. |f(2)| ?

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f (x) + f (\frac{1}{x}) = f (x) f (\frac{1}{x})

f (3) = 28

f (\frac{1}{3})

f (x)

is a polynomial in

x

(> 0)

satisfying the equation

f (x) + f (\frac{1}{x}) = f (x) f (\frac{1}{x})

f (2) = 9,

f (3) =

f (x)

is a polynomial satisfying

f (x) f (\frac{1}{x}) = f (x) + f (\frac{1}{x})

f (3) = 82

\int \frac{f (x)}{x^{2} + 1} d x =

f (x)

is a polynomial function such that

f (x) f (\frac{1}{x}) = f (x) + f (\frac{1}{x})

f (3) = - 80

f (x)

f (x) f (\frac{1}{x}) = f (x) + f (\frac{1}{x}) \forall x ϵ R - 0

where f(x) be a polynomial function and f(5) =126 then f(3)=

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