$9 x^{3} y + 41 x^{2} y^{2} + 20 x y^{3}$

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Solution

$9 x^{3} y + 41 x^{2} y^{2} + 20 x y^{3}$
Take out common in all terms,
$x y (9 x^{2} + 41 x y + y^{2})$
Above terms can be written as,
$x y (9 x^{2} + 36 x y + 5 x y + 20 y^{2})$
$x y [9 x (x + 4 y) + 5 y (x + 4 y)]$
$x y (x + 4 y) (9 x + 5 y)$

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Similar questions

For solving each pair of equations, use the method of eliminations by equating coefficients:

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