Why Trigonometry

Q.

The degree measure of a semi-circle is

1. $0^{\circ }$

2. ${360}^{\circ }$

3. ${180}^{\circ }$

4. ${90}^{\circ }$

Q. If tan2x =tan2/x then the value of x is

Q. A kite is attached to a 100m long string . Find the greatest height reached by the kite when its string makes an angle 60° with the level ground

Q. the length of the sides of a triangle are 8 cm, 15 cm and 17 cm . Perpendicular length from the opposite vertex to the side whose length is 17 cm i

Q. Find the value of x.

1. 30 degree
2. 60 degree
3. 90 degree
4. 45 degree

Q.

how to convert degree into radian?also write the value of 1 degree, 1 minute and 1 second.

Q.

Draw a triangle of sides 3, 4 and 6 centimetres. Draw three different right triangle of the same area .

Q. Which of the following is true for a triangle PQR?

1. PQ + PR < PQ
2. PQ + QR > PR
3. PR + PQ < QR
4. PQ + PR < PR

Q. How to find the value tan 40 degree

Q. 36. The sides of a triangle are 2006cm, 6002cm and k cm, k is a +ve integer.find the no of such possible trianles.

Q.

1. 23^°, 23^°

2. 23^°, 78^°

3. 29^°, 73^°

4. 29^°, 78^°

Q. 30.If angle B and angle Q are acute angles such that sin B = sin Q, then prove that angle B = angle Q

Q.

In triangle ABC , DE || BC, AD=1.2
DB=3.6, AE=1.6.What must be the value of EC?

1. 4.8

2. 6.0

3. 6.4

4. 3.2

Q.

How 11/24×180° = (165/2)°

Please explane in very simple form

Q.

Q.

Which of the following statements is correct?

1. As θ increases from 0° to 90°, the value of cosec θ increases

2. As θ increases from 0° to 90°, the value of sec θ decreases

3. cot θ is undefined for θ = 90°

4. tan 60° > tan 45°

Q.

The value of θ in √3tan2θ - 3 = 0 is

1. 45^o

2. 60^o

3. 90^o

4. 30^o

Q. In a $∆$PQR, if $\angle$P $-$ $\angle$Q = 42$°$ and $\angle$Q - $\angle$R = 21$°$, find $\angle$P, $\angle$Q and $\angle$R.

Q. If ABC is an equilateral triangle, then find AD.

1. 3 cm
2. 9 cm
3. 6 cm
4. 18 cm

Q. Solve (1 + cos y)(1 - sin y) for y = 45 degrees.

1. 0
2. 1
3. 0.5
4. 2

Q. In fig 8.17, $∆$XYZ is a right angled triangle and $\angle$XYZ = 90$°$ Write all trigonometric ratios of angle X and angle Z.

Q. From the given figure, find the value of cot x.

1. 12/13
2. 5/12
3. 5/13
4. 12/5

Q. In ∆ABC, if ∠A + ∠B = 125° and ∠A + ∠C = 113°, then ∠A = ?
(a) (62.5)°
(b) (56.5)°
(c) 58°
(d) 63°

Q.

When 0^o < θ < 90^o and 3tan²θ - 1 = 0. Then θ is equal to

1. 45^o

2. 90^o

3. 60^o

4. 30^o

Q. How can we solve that 3/2 of a right angle is 125 degree?

Q. CDE is an equilateral triangle formed on a side CD of a square ABCD. Show that ΔADE ≅ ΔBCE.

Q.

Sarosh and his brothers inherited a square piece of land from their ancestors. However, his share of the land was only an equilateral triangular piece, with one vertex as that of the square land and side equal to half of the square. Also, one side of Sarosh'��s land coincided with one side of the square land.

Sarosh wanted to fix a perimeter on his area and he had an anchor and a rope of length equal to half of that of the side of the square, to mark his territory. He fixes the anchor at one vertex, A.

Sarosh was given a set of cards instructing how to mark his territory. Sarosh being inquisitive, wanted to know

the reasons behind the instructions in the cards. Select the correct option for the matching of coloumn A and B from the given options

NOTE: While walking, Sarosh leaves footprints so that his path can be tracked.

A rope is said to be taut when it can not be stretched further, i.e it reaches its maximum length.

[Column A] Instructions on card

Walk along any side of the square till the rope becomes taut. Mark this point, say Q. When the rope becomes taut, with the anchor still at A, walk inside the field till you reach side AD (towards the sides AD and DC). Now put the anchor at Q and walk along side AB till the rope is taut. Now when the rope is taut, walk towards sides DC and CB (inside the field) till he meets his previous footprints (with anchor at A), at P. Join the points of intersection of his foot tracks to get the territory.

[Column B] Reason

Triangle is formed We need to get the length of the side of our triangle. This is similar to setting the compass length as the side of the triangle. Similar to drawing an arc, to find the point equidistant from the second vertex of the triangle. This is so that we need to find out what all points are at a distance equal to that of the side of the triangle.

1. 1 – D, 2 – B , 3 – C , 4 - A

2. 1 – B, 2 – D , 3 – C , 4 - A

3. 1 – B, 2 – A , 3 – D , 4 - A

4. 1 – A, 2 – D , 3 – C , 4 - B

Q. If $\sqrt{3}\mathrm{tan\theta }=2\mathrm{sin\theta }$ (0° < $\theta$ < 90°), then $2\mathrm{sin\theta }\cdot \mathrm{cos\theta }$ is
यदि $\sqrt{3}\mathrm{tan\theta }=2\mathrm{sin\theta }$ (0° < $\theta$ < 90°), तब $2\mathrm{sin\theta }\cdot \mathrm{cos\theta }$ है

1. tan30º
2. tan45º
3. sin45º
4. cos30º

Q. From the figure given below, find the value of 25 cos C.

1. 7
2. 17
3. 24
4. 25

Q. If $\angle$XPY = 135$°$, $\angle$XPZ = 175$°$ and the point Y is the interior of $\angle$ZPX, then find $\angle$YPZ.