# Calorimetry

## Trending Questions

**Q.**

1 kg of ice at 0∘C is mixed with 1 kg of steam at 100∘C. What will be the composition of the system when thermal equilibrium is reached? Latent heat of fusion of ice = 3.36 × 105 J kg−1, specific heat capacity of water = 4200 J kg ^{−1} K^{−1} and latent heat of vaporization of water = 2.26 × 106 J kg−1

2kg steam

2 kg ice

665gm water, 1.335 kg steam

665 gm steam, 1.335 kg water

**Q.**A lump of 0.10kg of ice at −10∘C is put in 0.15kg of water at 20∘C. How much water and ice will be found in the mixture when it has reached in thermal equilibrium.

(Specific heat of water =1kcalkg−1, specific heat of ice =0.50kcalkg−1 while its latent heat =80kcalkg−1)

- Ice is 16.75 gm , and water is 11.25 gm at .
- Ice is 6.75 gm , and water is 181.25 gm at .
- Ice is 108.75 gm , and water is 101.25 gm at .
- Ice is 68.75 gm , and water is 181.25 gm at .

**Q.**A 5 g piece of ice at - 20∘C is put into 10g of water at 30∘C. Assuming that heat is exchanged only between the ice and the water, find the final temperature of the mixture.

**Q.**A 5g piece of ice at −20∘C is put into 10g of water at 30∘C. Assuming that heat is enchanged only between the ice and the water, find the final temperature of the mixture. Specific heat capacity of ice =2100Jkg−1∘C−1. Specific heat capacity of water =4200Jkg−1∘C−1 and latent heat of fusion of ice 3.36×105 J kg−1.

- 20∘ C
- 30∘ C
- 0∘ C
- 10∘ C

**Q.**Find the result of mixing 10 g of ice at −10oC with 10 g of water at 10oC. Specific heat capacity of ice =2.1 Jg−1K−1, specific latent heat of ice =336 Jg−1 and specific heat capacity of water =4.2 Jg−1K−1

- 0.625 g ice will melt. Temperature will remain 0oC
- 0.625 g ice will melt. Temperature will increase to 5oC
- 10 g ice will melt. Temperature will increase to 5oC
- 10 g ice will melt. Temperature will remain 0oC

**Q.**In an industrial process 10 kg of water per hour is to be heated from 20∘C to 80∘C. To do this steam at 150∘C is

passed from a boiler into a copper coil immersed in water. The steam condenses in the coil and is returned to

the boiler as water at 90∘C. how many kg of steam is required per hour.

(Specific heat of steam = 1 calorie per gm°C, Latent heat of vaporization = 540 cal/gm)

- 1 gm
- 1 kg
- 10 gm
- 10 kg

**Q.**Calculate the amount of heat required to convert 5 kg of ice at 0∘C to vapour at 100∘C.

- 1.5×107J
- 3.5×107J
- 2.5×107J
- 4.5×107J

**Q.**Find the result of mixing 10 g of ice at −10∘C with 10 g of water at 10∘C. Specific heat capacity of ice = 2.1Jg−1K−1, specific latent heat of ice = 336Jg−1 and specific heat capacity of water = 4.2Jg−1K−1

- 6.25 g ice will melt. Temperature will remain 0∘
- 0.625 g ice will melt. Temperature will increase to 10∘
- 0.625 g ice will melt. Temperature will remain 0∘
- 6.25 g ice will melt. Temperature will increase to 10∘

**Q.**

**A piece of metal at 20**

^{o}C has a mass of 60g. When it is immersed in a current of steam at 100^{∘}C, 0.5g of steam is condensed on it. Determine the specific heat of metal, given that the latent heat of steam = 540 cal/g.**Q.**

Steam at 100∘C is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at 15∘C till the temperature of the calorimeter and its contents rises to 80∘C. The mass of the steam condensed in kg is

0.130

0.065

0.260

0.135

**Q.**The temperature at which water and ice exists together is:

- 273 K
- 373 K
- 300 K
- 0 K

**Q.**Calculate the amount of heat required to convert 1.00 kg of ice at −10∘C into steam at 100∘C at normal pressure. (Sice=2100 J kg−1K−1, Swater=4200 J kg−1K−1 Lfice=3.36×105 J kg−1 Lvwater=2.25×106 J kg−1)

- 3.03×106 J
- 4.03×106 J
- 5.03×106 J
- 5.03×106 J

**Q.**

On which of the following does the specific heat capacity of a body depend?

The heat impart

The mass of the body

Temperature

The material it is made up of

**Q.**A molten metal of mass 150 g is kept at its melting point 800∘C. If the specific heat capacity of metal is 200Jkg−1K−1, how much additional heat energy will the metal give out in cooling to −50∘C ?

- 2.55J
- 25.5J
- 255J
- 25, 500J