Introduction to Equations of Motion
Trending Questions
The brakes applied to a car produce a negative acceleration of 6 m/s2. If the car takes 2 seconds to stop after applying the brakes, calculate the distance it travels during this time. (Give your answer in m)
A car moving with a speed of can be stopped by applying brakes after at least . If the same car is moving with a speed of ., what is the minimum stopping distance
[3 Marks]
A car moving at speed one applying brake stops at a distance of . If same car move with the velocity , what distance it cover after applying the brakes.
Brakes are applied by a truck to produce retardation of 10 ms−2. If the truck takes 5 seconds to stop after applying the brakes, the distance covered by the truck before coming to rest is
125 m
150 m
175 m
200 m
Brakes are applied to a truck to produce an acceleration of –10m/s2. If the truck takes 5s to stop after applying the brakes, the distance covered by the truck before coming to rest is 250 m.
200 m
125 m
Brakes are applied to a truck to produce an acceleration of –10m/s2. If the truck takes 5s to stop after applying the brakes, the distance covered by the truck before coming to rest is 250 m.
200 m
125 m
Brakes are applied to a truck to produce an acceleration of –10 ms−2. If the truck takes 5 s to stop after applying the brakes, then find the distance covered by the truck before coming to rest.
- 250 m
- 125 m
- −125 m
- −250 m
- S1=S2
- S1=2S2
- S2=3S1
- S2=4S1
- 1350 m
- 1620 m
- 1482 m
- 1700 m
- Car
- Truck
- Both will cover the same distance
- Nothing can be decided
Brakes are applied to a truck to produce an acceleration of –10 ms−2. If the truck takes 5 s to stop after applying the brakes, then find the distance covered by the truck before coming to rest.
- 250 m
- 125 m
- −125 m
- −250 m
If the displacement of a body is in direct proportion to the square of the time lapsed, then the acceleration is
Increasing
Constant
Decreasing
Can't say
- 1350 m
- 1620 m
- 1700 m
- 1482 m
- S1=S2
- S1=2S2
- S2=3S1
- S2=4S1
- S1=S2
- S1=2S2
- S2=3S1
- S2=4S1
Brakes are applied to a truck to produce an acceleration of –10 ms−2. If the truck takes 5 s to stop after applying the brakes, then find the distance covered by the truck before coming to rest.
- 250 m
- 125 m
- −125 m
- −250 m
- 55 ms−1
- 65 ms−1
- 40 ms−1
- 70 ms−1
- The car would continue moving west with a velocity of 55 MPH
- The car would increase its velocity without changing acceleration
- The car would slow down but never reach 0 velocity
- The car would slow down and come to rest
- The car would slowly increase its velocity approaching but not reaching the speed of light