CI

Q.

A certain sum of money , invested for 4 years at 8 % p.a. simple interest , earns an interest of ₹ 10, 000. Find

(a) the sum of money

(b) the compound interest earned by this money in two years at 12 % p.a. compound interest

1. ₹ 31, 250 , ₹ 7950

2. ₹ 31, 250 , ₹ 39200

3. ₹ 30, 000 , ₹ 8000

4. ₹ 29, 250 , ₹ 6950

Q.

Find the compound interest on ₹ 20, 000 in 3 years, if the rate of interest for the successive years are 10%, 12%, and 15% respectively.

1. ₹ 8336

2. ₹ 7596

3. ₹ 8596

4. ₹ 9546

Q.

Find the sum invested if the difference between S.I. and C.I. on a sum for 2 years at $8\%$ per annum is ₹ 480

1. ₹ 55, 000

2. ₹ 75, 000

3. ₹ 85, 000

4. ₹ 80, 000

Q.

A principal of ₹ 50, 000 is invested at the rate of 10% for 2 years in compound interest. Find the compound interest and the difference between C.I and S.I.

1. ₹ 10, 500 , ₹ 500

2. ₹ 10, 500 , ₹ 1500

3. ₹ 10, 500 , ₹ 1000

4. ₹ 10, 000 , ₹ 500

Q.

If the interest earned in one year is ₹ 400 on a sum of money of ₹ 8000, then the principal under compound interest for the second year will be ₹ _______

1. ₹ 8400

2. 8000

3. ₹ 7600

4. 4400

Q.

Aditya borrowed ₹ 30, 000 from a bank to buy a Washing machine at a rate of 10% interest p.a. compounded yearly. What amount will he pay at the end of 2 years and 4 months to clear the loan?

1. ₹ 38, 510

2. ₹ 42, 510

3. ₹ 35, 510

4. ₹ 37, 510

Q.

If the compound interest earned on ₹30000 at 7% per annum is ₹4347, then find the time period (in years).

1. 2

2. $2\frac{1}{2}$

3. 3

4. 4

Q.

The difference between the final amount and the original principal is called _______ .

1. interest

2. principal

3. rate of interest

4. time period

Q. Which of the following is the correct formula to calculate the amount in case of Compound Interest?

1. $A=P(1+\frac{r}{100}{)}^t$
2. $A=P(1-\frac{r}{100}{)}^t$
3. $A=P(1+rt)$
4. None of the above

Q. Bacterial population doubles every hour. If there are 1200 bacteria now, when was 300 bacteria present?

1. 2 hours ago
2. 3 hours ago
3. 4 hours ago
4. 5 hours ago