# Median

## Trending Questions

**Q.**Calculate the median from the following data:

Marks below: | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 |

No. of students: | 15 | 35 | 60 | 84 | 96 | 127 | 198 | 250 |

**Q.**Find the median for the given data by drawing a 'less than ogive': [6 MARKS]

Class interval0−1010−2020−3030−4040−50Frequency4915148

**Q.**

Find the median of the first ten prime numbers?

**Q.**

From the following frequency distribution, find the median class:

Cost of living index1400−15501550−17001700−18501850−2000Number of weeks815218

**Q.**

If n2 =any of the given Cf then what is the median class

**Q.**

The table below gives the percentage distribution of female teachers in the primary school of rural areas of various States and Union Territories (UT) of India. Find the median, mean and mode of the data.

% of female teachers | $15-25$ | $25-35$ | $35-45$ | $45-55$ | $55-65$ | $65-75$ | $75-85$ |

No. of states/UT | $6$ | $11$ | $7$ | $4$ | $4$ | $2$ | $1$ |

**Q.**

Find the median of the following data distribution.

Marks obtained2029283342384325Number of students628241524120

28.5

29

30

40

**Q.**

Class Interval | $0-100$ | $100-200$ | $200-300$ | $300-400$ | $400-500$ | $500-600$ | $600-700$ | $700-800$ | $800-900$ | $800-900$ |

Frequency | $2$ | $5$ | $x$ | $12$ | $17$ | $20$ | $y$ | $9$ | $7$ | $4$ |

The median of the following data is $525$.

Find the value of $x$ and $y$, if the total frequency is $100$.

**Q.**

100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabet in the surnames was obtained as follows:

Number of letters1−44−77−1010−1313−1616−19Number of surnames630401644

Determine the median number of letters in the surnames. Find the mean number of letters in the surnames. Also, find the modal size of the surnames.

**Q.**Calculate the median from the following data:

Rent (in Rs.): | 15âˆ’25 | 25âˆ’35 | 35âˆ’45 | 45âˆ’55 | 55âˆ’65 | 65âˆ’75 | 75âˆ’85 | 85âˆ’95 |

No. of Houses: | 8 | 10 | 15 | 25 | 40 | 20 | 15 | 7 |

**Q.**

If ${a}_{1},{a}_{2},...{a}_{50}$are in GP, then$({a}_{1}-{a}_{3}+{a}_{5}-...+{a}_{49})/({a}_{2}-{a}_{4}+{a}_{6}-...+{a}_{50})$is equal to

${a}_{2}/{a}_{5}$

${a}_{4}/{a}_{6}$

${a}_{1}/{a}_{2}$

${a}_{6}/{a}_{1}$

**Q.**

If y is the mean proportional between x and z prove that

xyz(x+y+z)^3=(xy+yz+zx)^3

**Q.**

From the following data, find the median age of 100 residents of a colony who took part in Swachh Bharat Abhiyan:

Age(in yrs.) MoreNo. of residentsthan or equal to0501046204030204010503

**Q.**

The mean proportional between two numbers is 28 and their third proportional to them is 224. The two numbers are

**Q.**

The lengths of 40 leaves in a plant are measured correctly to the nearest millimeter, and the data obtained is represented as in the following table: Find the median length of leaves.

Length in mm | Number of leaves |

$118-126$ | $3$ |

$127-135$ | $5$ |

$136-144$ | $9$ |

$145-153$ | 12 |

$154-162$ | $5$ |

$163-171$ | $4$ |

$172-180$ | $2$ |

**Q.**The following is the distribution of height of students of a certain class in a certain city:

Height (in cms): | 160âˆ’162 | 163âˆ’165 | 166âˆ’168 | 169âˆ’171 | 172âˆ’174 |

No. of students: | 15 | 118 | 142 | 127 | 18 |

Find the median height.

**Q.**

Find two no. such that the mean propoortional between them is 28 and the third proportional to them is 224.

**Q.**Formula for calculating median of grouped data is:

l+[n2−cff]×h

- True
- False

**Q.**

Find the median of the given data:-

$5.6,7.2,1.8,4.3,9.1,2.6,3.4$

**Q.**

Using a graph paper, draw an ogive for the following distribution which shows the marks obtained in the General Knowledge paper by 100

Marks0−1010−2020−3030−4040−5050−6060−7070−80NO. of Student5102025151294

Use the ogive to estimate:

(i) the median.

(ii) the number of students who score marks above 65 .

38, 8

36, 8

8, 36

36, 10

**Q.**

The correct formula for finding the median of a grouped data is

**Q.**

Find the median class for the below distribution.

ClassCumulative frequency10−20320−301730−402440−503350−6051

- 20 - 30
- 30 - 40
- 40 - 50
- 50 - 60

**Q.**In a hospital, the ages of diabetic patients were recorded as follows. Find the median age. [CBSE 2014]

Age (in years) | 0−15 | 15−30 | 30−45 | 45−60 | 60−75 |

Number of patients | 5 | 20 | 40 | 50 | 25 |

**Q.**

A survey was conducted on 20 families in a locality by a group of students .What will be the mode of the data?

Age of family member0−2020−4040−6060−8080−100Number of students78221

21.85

22.85

23.87

24.87

**Q.**

If A.M of two terms is $9$ and H.M is $36$, then G.M will be

$18$

$12$

$16$

None of these

**Q.**

**Question 7**

The distribution below gives the weights of 30 students of a class. Find the median weight of the students.

Weight (in kg)40−4545−5050−5555−6060−6565−7070−75Number of students 2386632

**Q.**

Find the Median for the given data by drawing a 'less than ogive' :

Class Interval0−1010−2020−3030−4040−50Frequency51014168

31

35

28

29

**Q.**

Question 80(ii)

In Delhi University, in the year 2009-10, 49000 seats were available for' admission to various courses at graduation level. Out of these 28200 seats were for the students of General Category while 7400 seats were reserved for SC and 3700 seats for ST. Find the percentage of seats' available for students of SC Category and ST Category taken together.

**Q.**

Median Mark = 56.5, Passing marks: 39, % students got distinction = 20%

Median Mark = 56.5, Passing marks: 39, % students got distinction = 60%

Median Mark = 56.5, Passing marks: 30, % students got distinction = 20%

Median Mark = 50.5, Passing marks: 39, % students got distinction = 20%

Median Mark = 50.5, Passing marks: 30, % students got distinction = 20%

Median Mark = 50.5, Passing marks: 39, % students got distinction = 10%

**Q.**

**Question 2**

During the medical check-up of 35 students of a class, their weights were recorded as follows:** **

Weight (in kg)Number of studentsLess than 380Less than 403Less than 425Less than 449Less than 4614Less than 4828Less than 5032Less than 5235

Draw a less than type ogive for the given data. Hence, obtain the median weight from the graph verify the result by using the formula.